Velocity is the common term used in physics when direction is considered. The consistency in velocity rate tells about the uniformity and called as uniform velocity. As a illustration consider a car starting from rest and moving at a speed of 60 km/hr on a straight road. If its in uniform velocity It covers an equal distance of 1 km in 1 minute. |

A body is said to have uniform velocity if it covers equal distance in equal intervals of time in a particular direction how much ever small or big the interval might be. Here the displacement will also be equal for the intervals of time. In simple words the constant speed in a fixed direction has uniform velocity or else the velocity is said to be variable.

The velocity is the displacement covered in the given time. Uniform velocity is that where uniformity is maintained consistently for the equal time interval. It is given byUniform Velocity = $\frac{Uniform\ Displacement}{Equal\ time\ interval}$

= $\frac{\Delta\ x}{\Delta\ t}$

Here $\Delta$ x is the distance covered and $\Delta$ t is the time interval.= $\frac{\Delta\ x}{\Delta\ t}$

The uniform velocity graph shows the change in velocity for every equal time interval. Below graph shows that change in velocity of 10 m/s for every time interval of 2s.

You could observe that any body in circular path changes its direction continuously even though speed is constant. It says that the body is continuously accelerated. This acceleration acts towards the center of the circular path is known as centripetal acceleration. If a body moves along a circular path with constant speed that its acceleration is uniform and is said to be in uniform motion.

**Here are some problems on uniform velocity you can go through it :**

### Solved Examples

**Question 1:**What is the velocity of a plane that travels 700 m in 3 s?

**Solution:**

Given: Displacement = 700 m, time taken t = 3s

The Velocity is

v = $\frac{Displacement}{time}$

= $\frac{700\ m}{3\ s}$

= 233.33 m/s.

**Question 2:**A man covers 50 m in 10 s and another man covers 30 m in 6s. Are they moving with uniform velocity?

**Solution:**

Given: Displacement of first man x

_{1}= 50 m, time taken t

_{1}= 10s,

Displacement of second man x

_{2}= 30 m and time taken t

_{2}= 6s

Velocity of 1st man = $\frac{x_1}{t_1}$ = $\frac{50 m}{10 s}$ = 5 m/s

Velocity of 2nd man = $\frac{x_2}{t_2}$ = $\frac{30 m}{6 s}$ = 5 m/s

Hence both are having same uniform velocity.

**Question 3:**A car travels at 30 km/hr speeds up to 80 km/h in 10 s. Calculate its acceleration.

**Solution:**

Given: Initial velocity u = 30 km/hr, Final velocity v = 80 km/hr, time taken t = 10 s

To convert km/hr into m/s : 1 km/hr = $\frac{1000/ m}{3600/ s}$ = $\frac{5}{18}$ m/s

Initial Velocity u = 30 km/hr = $\frac{30 \times 5}{18}$ = 8.33 m/s

Final velocity v = 80 km/hr = $\frac{80 \times 5}{18}$ = 22.22 m/s

The acceleration is a = $\frac{v - u}{t}$

= $\frac{22.22 m/s - 8.33 m/s}{10 s}$

= 1.389 m/s

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