You could see many physics behind many activities in your daily life like you use a hand crank to raise a bucket of water from the well. To raise the bucket the crank must be applied with enough force.The turning point at which the force applied is what we call torque!

A rotational or twisting effect of a force due to the force acting at a
distance from the axis of rotation is what we call torque. It is the
measure of twist in the object. It is used to measure of the turning force on
an object such as bolt or flywheel.
If $\theta$ is the angle between r and F. Torque is defined as$\tau$ = r $\times$ F = rF sin $\theta$Here
r is the length of the lever arm vector or the position vector relative
to fulcrum and F is the force vector or force acting on the particle.
The SI unit of torque is Newton meter (Nm) and dimensional formula is [M L^{2} T^{ 2}].If the force F is perpendicular to radius r then you can eliminate sin $\theta$ then torque $\tau$ = r $\times$ F.
Torque is that what decides how much force should act that makes a body
to rotate. The object rotates about an axis from a point O we call the force F. The distance from the point O to the
point where force acts is the moment arm or the radius of the arm and is denoted as r.
Referring the above figure
A force applied at a distance from the lever arm is its torque. It is given as$\tau$ = r $\times$ F
Here r is the particles position vector and F is the force applied. The magnitude $\tau$ of the torque is given by$\tau$ = rF sin $\theta$
Here r is the distance from the axis of rotation to the particle and F is the magnitude of force applied and $\theta$ is the angle between the position and force vectors.The torque tells about the rate of change of angular momentum L
$\tau$ = $\frac{dL}{dt}$
Here L is the angular momentum and t is the time. If many torques are acting on the body the rate of change of angular momentum is
$\tau_1$ + $\tau_2$ + ....... + $\tau_n$ = $\tau_{net}$ = $\frac{dL}{dt}$
For the rotation about the fixed axis the angular momentum is
L = I $\omega$
Here I is the moment of inertia and $\omega$ is the angular velocity. The net torque is
$\tau_{net}$ = $\frac{dL}{dt}$ = $\frac{d(I \omega)}{dt}$ = I $\alpha$
Here $\alpha$ is the angular acceleration expressed in radian per second square (rad/s^{2}).
The SI unit of torque is Newton meter (Nm) or Joule per radian. In imperial and US unit it is measured in foot pounds (ft.lbf), inch pounds or even inch ounces are used.
Here are some common used torque units:
Unit in terms of 
Torque Units 

dyne (Metric unit)  dyne Centimeter
 
gram (Metric unit) 
gram force centimeter


kilogram (Metric unit) 
kilogram force centimeter


newton (Metric unit) 
newton centimeter


ounce (US unit)  ounce force foot
 
pound (US unit) 
pound force foot

A conversion factor is always necessary. Since SI unit of torque is newton meter lets us convert all other units in terms of it:
1 Newton meter = 100 newton centimeter = 1000 newton millimeter = 0.001 kilonewton meter = 100000 dyne meter = 10000000 dyne centimeter = 100000000 dyne millimeter = 0.101971621 kilogramforce meter = 10.19716213 kiloforce centimeter = 101.971621298 kgf mm = 101.971621298 gf m = 10197.162129779 gf cm = 101971.62129779 gf mm = 11.800994078 ozf ft = 141.611928936 ozf in = 0.737562121 lbf ft = 8.850745454 lbf in.
1 Newton meter = 100 newton centimeter = 1000 newton millimeter = 0.001 kilonewton meter = 100000 dyne meter = 10000000 dyne centimeter = 100000000 dyne millimeter = 0.101971621 kilogramforce meter = 10.19716213 kiloforce centimeter = 101.971621298 kgf mm = 101.971621298 gf m = 10197.162129779 gf cm = 101971.62129779 gf mm = 11.800994078 ozf ft = 141.611928936 ozf in = 0.737562121 lbf ft = 8.850745454 lbf in.
The torque is the rotational force or twist in the body. Horse power is the measure of the torque rate acting over time. Torque is the turning effort of the engine. The rpm is the rotational speed.
Horse power is used as unit of engine power measurement that determines the engine speed and torque. It is given as
Horse power = $\frac{Torque \times rpm}{5250}$
Horse power = $\frac{Torque \times rpm}{5250}$